by
Rndirk » Tue Jan 03, 2017 9:05 am
Hi,
Welcome to the forum.
A peak that shows up in your chromatogram consists of data points which are connected by a line. If you have 3 data points over 1 peak, it will look like a distorted triangle. This is not enough for quantitative integration. On the other hand, 50 data points over 1 peak with give you a "noisy" peak with too much features. You see that there a optimal amount of data points over 1 peak: you want somewhere between 12-20.
With single or triple quadrupole MS detection, you typically want to look at more than 1 ion (transition) at a given moment. Your instrument can not measure them at the same time, it has to switch its filter (quad) rapidly between different masses. Here's where dwell and cycle time comes in.
Assume you want to measure 5 transitions over a certain period (also called windows).
Dwell time: the amount of time it measures 1 transition. Suppose you set this to 50 msec for each transition
Cycle time: The time it takes to aquire all transitions. This is 250 ms (50 x 5). (Note this is actually a little bit higher because it takes a few ms to switch between transitions).
What you should do with this information is optimize the amount of data points over your peak and give your instrument a minimal amount of dwell time per transition. Minimal dwell time is instrument dependent. For quantitative work, i use a minimum of 10 msec.
In the example above, it takes 250 ms for 1 cycle, so 5 transitions are measured once each during this time, then the cycle repeats. Each second, the cycle repeats 4 times (1 second/0.250 seconds). This means, if component X starts eluting at second 500 in your method , and ends eluting at second 503, it will have 3 sec x 4 = 12 data points over its peak.
The peak width is an important factor here, and depends on a lot of parameters in your method. You should check what peak widths you have and change the settings accordingly. In a given window, you want to optimize the settings for the narrowest peak. For example, for a narrow peak of 2 seconds, you want to lower the dwell time in the example above to 40 ms / transition (total dwell time 40*5 = 200ms), so you have 5 cycles per second => 10 data points over a 2 second peak.
Practice: You want to measure 8 components. Narrowest peak is 2.5sec. How much dwell time per component to get 12-20 data points per peak?