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- Posts: 43
- Joined: Thu May 23, 2013 2:54 pm
My software automatically calculates the value of impurity. The result is 0.048% The LOQ Value is 0.05%!
My result is > or < or = that LOQ?
Thanks
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Discussions about HPLC, CE, TLC, SFC, and other "liquid phase" separation techniques.
I worked in metrology for a while. I knew I was entering an alternative reality when the marks for my entrance exam were given to three significant figures !Strewth! I'm outclassed completely! If I want to finish that document before retirement age, I'd better develop a faster style of reading. It is great to know that these issues are being dealt with by people with brains the size of a smallish planet. Thanks for the link, though, it is actually really interesting.
It's not all bad - speed cameras for traffic offences have to be calibrated against standards that are ultimately traceable to the speed of light in a vacuum. Similarly with blood alcohol, reference materials trace to the kilogram and mole. These don't go to jury trial though.Yup, it's an alternative reality, especially for those of us who thought a guide for metrology was a girl who likes the weather.
It's a pity, though, that other walks of life take so little care about propagation of errors, precision, and confidence intervals, especially in contexts where the result matters intensely. For example, I can't see any point in the forensic analyst worrying about detection limits and statistical quality of his results when the court that finally makes the decision about guilt can't be bothered to define what it means by "beyond reasonable doubt", as decided by 12 good men and true?
Wrong. The very first answer from Tom is correct. Ignore everything and everybody that disagrees with it.No, your value will be 0.048%, reported as less than the LOQ (so, <LOQ (0.048%))
I don't understand: my LOD is 0.05& not 0.050%
Mi value is 0.048 (aprox 0.05)
Then... 0.05% or 0.05(<LOD) ??
Right?
Wrong. The very first answer from Tom is correct. Ignore everything and everybody that disagrees with it.No, your value will be 0.048%, reported as less than the LOQ (so, <LOQ (0.048%))
I don't understand: my LOD is 0.05& not 0.050%
Mi value is 0.048 (aprox 0.05)
Then... 0.05% or 0.05(<LOD) ??
Right?
Peter
Refer to my previous answer.Wrong. The very first answer from Tom is correct. Ignore everything and everybody that disagrees with it.
I don't understand: my LOD is 0.05& not 0.050%
Mi value is 0.048 (aprox 0.05)
Then... 0.05% or 0.05(<LOD) ??
Right?
Peter
OK!!!
So... my final result is 0.048%
And I report?
1) 0.05%
2) 0.05% <LOD
LOD=0.05%
Limit <1.00%
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