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Linearity problem with LC-MS MRM

Discussions about GC-MS, LC-MS, LC-FTIR, and other "coupled" analytical techniques.

6 posts Page 1 of 1
Hi everybody

I have recorded a calibration curve 10-150 µg/L of a specific compound, MRM with three daughter ions. This is the response of the standards:
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There is no range where the response is independent from concentration. Can I use this method together with quadratic calibration?
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My gut-feeling is: yes, but is there an experience based or linterature confirmed answer to this question?

Thanks in advance
Jörg
Can I use this method together with quadratic calibration?
Yes. I also recommend to use the internal standard calibration.
Yes. I also recommend to use the internal standard calibration.
With internal standard, do you mean deuterated standard? Wouldn't the response of the deuterated compound be influenced by the total concentration deuterated+unlabeled?
(btw. deuterated standard is not available for this compound)
do you mean deuterated standard?
Not only. You can use and other isotope-labeled (13C etc.) derivative of analyte. You also can use non-isotope-labeled IS (homologue etc.), but isotope-labeled IS is preferred.
Wouldn't the response of the deuterated compound be influenced by the total concentration deuterated+unlabeled?
No, if, of course, concentration of analyte will not give the ion suppression (Ca >> Cis).
yes, the response to a deuterated standard does depend on the summed concentration of the deuterated standard itself and the unlabelled compound (and also anything else that coelutes).

You can see this because if you create a standard curve using variable amounts of unlabelled compound, and constant amount of deuterated, you will see that the response for the deuterated will drop off. Some software will automatically show you a calibration curve for the internal standard (it will be an external calibration because the internal standard doesn't have its own internal standard...!!), and this will make it very clear. It will be a single-point calibration, and unless the range of your unlabelled calibration curve is very narrow, the single-point calibration will look awful, with very bad replicate points.

But it doesn't matter. In fact this is why we added the internal standard. Already with external standard calibration it didn't matter provided you fitted the calibration curve properly. The assumption with external calibration and a nice curvy curve-fit is that if ionisation efficiency is lower at 10uM than 7uM, this is already accounted for in the curve's shape, and we assume that the effect is always the same, whether it's a standard at 10uM or a sample at 10uM. Internal calibration goes a step further and acknowledges that 10uM in a sample might mean 10uM + 5uM rubbish, and be more severely affected than 10uM pure sample. So we look at it relative to 2uM (for example) internal standard. This means that if there is extra junk in the sample that means we measure the 10uM sample with only half the efficiency we managed in the standard, we also see only half what we'd expect of the internal standard - the ratio remains the same, and the result gives the correct answer, even though all the peak areas involved are less than in the standards.

This is also why internal standard calibrations often give much better linearity than external standard. The external standard curves off because of the varying ionisation efficiency. The internal doesn't because when the external calibration peak area of unlabelled analyte has dropped to only 70% of what you expected, the internal standard peak area has also dropped to only 70%. There is a direct link between the scatter of those internal standard points in my previous paragraph, and the improvement in linearity!
OF course you can use a quadratic curve fit. A linear curve fit is just a special case of a more generalized quadratic curve and only exists in limited concentration ranges for special cases.
Mark Krause
Laboratory Director
Krause Analytical
Austin, TX USA
6 posts Page 1 of 1

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