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- Posts: 78
- Joined: Sun Oct 03, 2010 10:26 pm
I prepared 0.5 N methanolic NaOH weighing .2g of NaOH into 10 ml of MeOH. It took NaOH quite some times to dissolve.
I used 3 ml of this methanolic solution to mix with 0.08 g (80 mg) o extra virgin olive oil to perform saponification before derivatizing the mixture (olive oil + NaOH) with 12% (1.5M) BF3.
How would I go about calculating the mass of 3 ml methanolic NaOH used in saponification since I could see that the .5N mathanolic NaOH was a bit saturated? I took 3 ml of methanolic NaOH, making sure that the solid pieces of NaOH were left behind.
MW of NaOH = 39.99 g/mol
Density of NaOH = 2.13 g/ml
