
 Posts: 2
 Joined: Thu Jul 05, 2018 8:40 pm
I have a liquid sample sample that I am extracting and quantifying an analyte in the liquid.
The extraction process is straight forward.
~3 mg of sample+ 3ml MeOH sonicate, inject
the sample matrix is essentially water, thus fully miscible in MeOH
My question is the Solvent amount in hte calculation. Do I multiply by the total volume of MeOH(3ml) or by the total volume of 6ml
I would like to find the concentration in mg/g my calculation is
analyte amount in ppm * Dilution
(((analyte amount in ppm*dilution factor)*((amount of solvent(ml)/100)/sample weight (g))/10)
example
Sx ppm result 100.00 ppm
Dilution 1
Sx weight 3.00g
solvent amount ?
the total volume is 6ml
if I plug in 6ml my result is 0.19 mg/g
If I use just the amount of MeOH the result 0.10 mg/g
Which would be correct?
The extraction process is straight forward.
~3 mg of sample+ 3ml MeOH sonicate, inject
the sample matrix is essentially water, thus fully miscible in MeOH
My question is the Solvent amount in hte calculation. Do I multiply by the total volume of MeOH(3ml) or by the total volume of 6ml
I would like to find the concentration in mg/g my calculation is
analyte amount in ppm * Dilution
(((analyte amount in ppm*dilution factor)*((amount of solvent(ml)/100)/sample weight (g))/10)
example
Sx ppm result 100.00 ppm
Dilution 1
Sx weight 3.00g
solvent amount ?
the total volume is 6ml
if I plug in 6ml my result is 0.19 mg/g
If I use just the amount of MeOH the result 0.10 mg/g
Which would be correct?