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				Calculating limit of detection for nonresolved peaks
				Posted: Tue Sep 04, 2007 11:57 am
				by degenchem
				I have an application were I need to calculate the limits of detection and quantifiaction for a small peak which comes on the tail of a much larger peak. 
Given that the LOD is 3x and the LOQ is 10x the noise, it seems to me that just taking the baseline noise of a blank would underestimate the LOD/LOQ, or am I wrong? The peaks are integrated by dropping a line to the baseline (no "tangential" or "valley-to-vallley" integration).
How should I calculate the LOD/LOQ in such cases?
			 
			
					
				
				Posted: Tue Sep 04, 2007 2:00 pm
				by AdrianF
				If you can't use skimming you are wasting your time - the integration is not fit for purpose. Your only hope is to improve the chromatography to resolve the peak or use a different integration package!
			 
			
					
				
				Posted: Tue Sep 04, 2007 2:11 pm
				by bartjoosen
				another approach to LOD and LOQ is to use the standard error and slope of the calibration line at near LOQ level.
See page 15: 
http://www.ich.org/LOB/media/MEDIA417.pdf
Bart
 
			
					
				
				Posted: Tue Sep 04, 2007 2:49 pm
				by Jumpshooter
				So, inject increasing amounts of your sample extract on your LC column, then collect the eluates at the waste end of  your LC setup that correspond to the Tr for the "low area peaks".  In this way you can collect increasing amounts of the compound that is giving the "low area peak".   Put the different "amounts" in autosampler vials---use these as your Calibrants on the next analytical run to assay the "low peak area compound".  Then, you will have generated a standard curve that displays "low peak area compound" amount vs. "peak area".  Voila! your calibration that will enable you to quantify (LOQ).  You can also do serial dilutions to further examine the LOQ
			 
			
					
				
				Posted: Tue Sep 04, 2007 3:56 pm
				by AdrianF
				It would be helpful if you could post a typical chromatogram.
			 
			
					
				
				Posted: Tue Sep 04, 2007 4:32 pm
				by bartjoosen
				So, inject increasing amounts of your sample extract on your LC column, then collect the eluates at the waste end of  your LC setup that correspond to the Tr for the "low area peaks".  In this way you can collect increasing amounts of the compound that is giving the "low area peak".   Put the different "amounts" in autosampler vials---use these as your Calibrants on the next analytical run to assay the "low peak area compound".  Then, you will have generated a standard curve that displays "low peak area compound" amount vs. "peak area".  Voila! your calibration that will enable you to quantify (LOQ).  You can also do serial dilutions to further examine the LOQ
Maybe I missed something, but you can never be sure about the exact amount in your vial? It's diluted with mobile phase, so if you inject it again from a collected fraction, it's still more diluted on the column...
Bart
 
			
					
				
				Posted: Tue Sep 04, 2007 4:48 pm
				by Noser222
				Using the peak height instead of the area may be more beneficial for your purpose, assuming the situation isn't too bad.
			 
			
					
				
				Posted: Wed Sep 05, 2007 8:11 am
				by degenchem
				Thanks for your input so far. Here is a sample chromatogram:
 
I have the "small peak" compound available in  pure form, so I can easily calculate the LOD/LOQ with no obstructing peaks. It just seems like the value is too low for the sample matrix shown in the chromatogram above. 
As for the slope of the calibration line/standard error method -- wouldn't that method also underestimate the LOD/LOQ in this case?
 
			
					
				
				Posted: Wed Sep 05, 2007 12:43 pm
				by philippem
				Hi,
Is it possible to change your mobile phase  compoition or gradient profile ? I assume you are using gradient. 
Philippe
			 
			
					
				
				Posted: Wed Sep 05, 2007 12:50 pm
				by degenchem
				Hi,
Is it possible to change your mobile phase  compoition or gradient profile ? I assume you are using gradient. 
Philippe
Unfortunately the method can't be changed at this point, so we'll have to live with the poor separation.
 
			
					
				
				Posted: Wed Sep 05, 2007 2:18 pm
				by AdrianF
				If you are unable to change the chromatographic conditions you must change the integration method to give a more accurate idea of the area. The current area will be about double the true area of created by that substance.
PS why are you unable to change the conditions? If it is important to quantitate that the conditions need changing.
			 
			
					
				
				Posted: Wed Sep 05, 2007 2:19 pm
				by HW Mueller
				But you know that your results are wrong, so why continue?
			 
			
					
				
				Posted: Wed Sep 05, 2007 3:02 pm
				by philippem
				taking into account the last two remarks, one can say that the method was not (yet) completely developped, and probably  also not validated ! 
so why couldn't you change it to have a better separation between the peaks
anyhow succes
Philippe
			 
			
					
				
				Posted: Wed Sep 05, 2007 6:12 pm
				by bartjoosen
				Thanks for your input so far. Here is a sample chromatogram:
I have the "small peak" compound available in  pure form, so I can easily calculate the LOD/LOQ with no obstructing peaks. It just seems like the value is too low for the sample matrix shown in the chromatogram above. 
As for the slope of the calibration line/standard error method -- wouldn't that method also underestimate the LOD/LOQ in this case?
Do you have the "big" peak also in pure form?
Otherwise you can do an accuracy test, and see if there is a significant bias. If so, the method isn't sufficient to quantitate the minor peak, and you can't determinate an LOD/LOQ (or an amount....)
If it is accurate, the slope/se method wil be good enough to estimate the LOD/LOQ.
If you are afraid to underestimate, you can integrate valley to valley, this will overestimate your LOD/LOQ.
Bart
 
			
					
				
				Posted: Wed Sep 05, 2007 7:42 pm
				by tom jupille
				Dyson put the question into perspective almost a decade ago:
“. . . errors arising from peak overlap are introduced by the algorithms of perpendicular and tangent separation and cannot be eliminated by anything but better chromatography. Integrators are able to generate a highly precise and totally inaccurate set of results for all the foregoing examples.â€