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Accuracy (Recovery) Issue – sample diluent with citrate

Discussions about HPLC, CE, TLC, SFC, and other "liquid phase" separation techniques.

4 posts Page 1 of 1
Hi there,

We have experienced issues recently with an accuracy spiking method validation exercise, spiking drug into a liquid nebulizer solution that contains 10 mM of a citrate buffer. The concentration of drug is prepared accurately at about 5 mg/mL. The drug itself is a zwitterionic .HCL salt. The sample preparation for LC injection involves a 50 fold dilution with 25/75 AcN/water to 0.1 mg/mL concentration. So the final sample diluent contains 2% v/v of 10 mM citrate buffer.

The assay standards are prepared slightly differently, by dissolving directly into a 25/75 AcN/water v/v diluent. So there is no citrate in these standard solutions.

Assaying the accuracy (spiked) validation samples against the standards we consistently got between 93-94% recoveries (outside of our validation SOP criteria). We then investigated adding different levels of citrate to the samples and obtained the following results.


Citrate Addition % v/v Drug Recovery %
0 99.9
1 97.1
2 95.6
4 94.7
6 94
8 94.2
10 94.1

So there appears to be some kind of leveling off effect with the citrate concentration in the sample solution.What could be the cause of this missing 6-7% when we run mismatched samples and standards? Is it some kind of ion-pairing/chelating effect with citrate that is causing a decrease in our assay recovery by LC? It is the first time I have come across something like this of this big a significance.

Consequently when we added 2% v/v citrate to our standard diluent preparation we achieve ca. 100% recoveries for our samples. I also compared UV stand-alone spectra of standards (no citrate) with standards with 2 and 10% citrate (diluted from the same stock standard so all at the same concetration) and there was perfectly overlay - i.e. no shifts in response or wavelength.
Maybe something along the lines of the "strong diluent effect" where the presence of the citrate alters the equilibria a bit until the injected sample gets diluted by mobile phase (the same kind of thing you see if you inject a sample dissolved in 100% organic)? In that situation, the peak shapes with/without citrate might be subtly different, enough to integrate slightly differently (yes, I'm hand-waving here!).

Regardless, matching the sample and standard diluents as you have done seems to me to be the most appropriate fix.
-- Tom Jupille
LC Resources / Separation Science Associates
tjupille@lcresources.com
+ 1 (925) 297-5374
Regardless, matching the sample and standard diluents as you have done seems to me to be the most appropriate fix.

That's also what we would do.
playing devil's advocate, if you genuinely have some strange mechanism by which citrate is actually removing analyte from the system (e.g. some weird ion-pair effect by which it causes a small amount of active ingredient to bind strongly enough to plastic tubes that you lose it...), then by matching your standards to the samples, you achieve a situation where all of your results are uniformly wrong. Neither the samples, nor the standards, contain what you expect, but since they agree about what they contain, everyone is happy...
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