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Static sorbtion

Discussions about HPLC, CE, TLC, SFC, and other "liquid phase" separation techniques.

4 posts Page 1 of 1
Hello colleagues.
I have to ask you a one question. It belongs to just a theoretical issue. But I'm trying to transfer theory into practice. Faced with the problem in the calculation of the statics sorption process.

After the introduction of substances into the analytical column, are started the sorption processes such as moving sorbate to the sorbent, and a first of part concentrated on the sorbent, while another part of substance remains in solution. Tell me how practically I can calculate the concentration of sorbate on the sorbent?

p.s. I want to understand the affinity of the sorbent to the sorbate, the strength of their interaction and thus the correct choice for the production method.

Thank you, very much!
With best regards!
Dmitry.
When the path is over and passed successfully, it's nice to remember even the mistakes ...
Hí dRima,

If I understand your question correctly, you are interested in the Retention Factor = K

http://teaching.shu.ac.uk/hwb/chemistry ... chrom1.htm


Best Regards
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Dancho Dikov
Hello Danko! Thank you for your reply!
But I mean no retention factor.
I am trying to calculate the capacity factor (ratio of Henry (private)).

It is defined as the ratio of the mass sorbate, which is adsorbed in a layer of 1 cm3 and the mass of sorbate in solution (in the same layer 1 cm3).

Thank you!
With best regards!
Dmitry
When the path is over and passed successfully, it's nice to remember even the mistakes ...
Danko, I have found more correctly determination.

The distribution equilibria involved in chromatography involve the transfer of an analyte between the mobile and stationary phases. The equilibrium constant K for this reaction is called the distribution constant, the partition ratio, or the partition coefficient,
K = cS/cM, where
"cs" is the molar concentration of the solute in the stationary phase and "cM" is its molar concentration in the mobile phase.
"K" is constant over a wide range of solute concentrations.

Thank's!
With best regards!
Dmitry.
When the path is over and passed successfully, it's nice to remember even the mistakes ...
4 posts Page 1 of 1

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