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LOD and LOQ in %

Discussions about HPLC, CE, TLC, SFC, and other "liquid phase" separation techniques.

3 posts Page 1 of 1
Hi all,

I got the values for LOD and LOQ in µg/mL for my the related impurities by HPLC. Now i have been asked to report them in %.with what respect i can convert them into %.Can anyone please explain?

Thanks
Suri
surendra.k

Tradtionally I've seen it reported as a percentage of the concentration of your main peak of interest. For example, say your main peak is at a concentration of 5.0 mg/mL and the LOQ of your impurity is 0.01 mg/mL then your LOQ as a percentage is (0.01 mg/mL) / (5.0 mg/mL) = 0.2%. Does that make sense?

If I've explained that poorly, or just flat out incorrectly, I'm sure someone will happily point out the error of my ways.
Hi Blazer,
Thank you very much for your reply.Yes that make sense.
Thanks.
surendra.k
3 posts Page 1 of 1

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