-
- Posts: 214
- Joined: Wed Dec 30, 2009 4:51 am
thanks if you can clarify for that.
Advertisement
Discussions about HPLC, CE, TLC, SFC, and other "liquid phase" separation techniques.
The signal of the UV detector is A = E*d*c, where E is the extinction coefficient of your analyte, d is the length of the path over which the signal is measured, and c is the analye concentration. Prep UV cells have a shorter path length, and the signal becomes lower when you change to a prep cell.
In prep chromatography, you should stay away from the absorption maxima to keep the signals within the (linear) range of the detector.
Not sure why you care about the "linear range" of a detector when you are doing preparative chromatography. When people do prep and exchange an analytical flow cell to a prep flow cell, they want to reduce the signal and are not worried about sensitivity. "Linear range" takes both the upper limit and the noise into account.
For an in-depth understanding of the subject of UV/Vis detectors, I recommend A. C. Gilby, Encyclopedia of Separation Science, Chromatography:Liquid/Detectors:Ultraviolet and Visible Detection.
Someone correct me if I'm wrong here, but I think the answer is 'It depends'. The extinction coefficient refers to how strongly your analyte absorbs UV at the wavelength you're using - hence Uwe's advice to not use the absorption maxima of your analyte in preparative chromatography. Therefore, the two factors that become important in Uwe's equation are the extinction coefficient and the concentration, when the path length is fixed.
For example, you could have a low to moderate concentration of an analyte saturating your detector when you are at the absorption maxima of that analyte, or you could have a high concentration of your analyte saturating your detector when you're at a wavelength that is not the absorbance maxima of your analyte.
I don’t think Jiang295 cares about the linearity in connection with the purification target’s amount.
I think the goal in this context is to examine the system’s ability to perform a gradient.
So, if I were correct in understanding the case properly, I’d recommend a repetition of the experiment using 0.5% acetone and comparing the outcome to the result obtained with 1 % acetone. If the traces are parallel then you don’t have a problem with the dynamic range of the detector. If not parallel then you’ll know what’s the problem.
As for the reason why the dynamic range could be reduced even though the abs. max is below 1 AU, there could be other explanations than analyte saturation. Typical examples are dirty flow cell window, low lamp energy etc.
Best Regards
You ran a linear gradient with water and 1% acetone - right?
And the detector output didn't schow a straight line- right?
The max absorbance was well below 1 AU - right?
And now you don't know wether your pumps underperform or detector isn't for some reason linear in that region - right?
So why dont you simply check linearity of the detector? Prepare acetone solutions 0.5, 1, 1.5, 2, 2.5, 3, 4, 5 % and injet the directly with a syring in the detector^, read the output absorbtion value and put it in a spreadsheet.
Alternatively you could inject the solutions with the autosampler.
Alex
Separation Science offers free learning from the experts covering methods, applications, webinars, eSeminars, videos, tutorials for users of liquid chromatography, gas chromatography, mass spectrometry, sample preparation and related analytical techniques.
Subscribe to our eNewsletter with daily, weekly or monthly updates: Food & Beverage, Environmental, (Bio)Pharmaceutical, Bioclinical, Liquid Chromatography, Gas Chromatography and Mass Spectrometry.