To expand on Dr. Neue's explanation, I'll step through the basic calculations for you on a hypothetical extraction, in case it's the math that's tripping you up:
1.  You have an initial sample volume/mass, e.g. 10 grams of soil.  
2.  You perform your extraction - liquid-liquid, SPE, etc.  Eventually you are left with a solvent extract of your original sample, with a known volume.  You can concentrate this extract by evaporation to achieve lower limits of quantitation, if necessary.
3.  You calculate your extraction ratio from your initial sample amount and your final extract amount - e.g. 20 mL final extract volume from a 10 g initial sample mass = 20 mL / 0.01 kg = 2000 mL / kg extraction multiplier.  
4.  You can then multiply this extraction ratio by your lowest calibration concentration (cancelling the units along the way) to find the relation of your extract to your calibration curve.  For example, say your lowest calibration point is 1 ug / mL, and your extraction ratio is 2000 mL / kg.  After converting units, you can equate your 1 ug / mL lowest calibration point to a 2000 ug / kg or 2 mg / kg Limit of Quantitation (LOQ).  You can also relate it to your upper range of quantitation by multiplying the same extraction ratio by your highest calibration point.  
5.  For unknown samples, you'll take the response from your unknown, equate it to a concentration via your calibration curve equation, then multiply by your extraction ratio to determine how much of whatever it is you're looking for was in your original sample.
Hope this was helpful.