What is the correct data processing method?
Posted: Mon Mar 15, 2021 11:02 pm
Hi,
There are two analysts in my work that are disagreeing on how to process HPLC data. I'm not sure with which way to go.
We are analysing an impurity in a solution of various components - acids, methanol etc. Our goal is to determine if the solution contains <1,000ppm of impurity and if so, it's good to be used.
We pipette 0.1ml into a 10ml volumetric flask, record the actual weight of the sample and make up to the mark with ultrapure water and then obtain a ppm result from the HPLC.
Parameters:
Dilution factor: 100
Example sample weight (0.1ml sample): 0.1016g
Example Machine ppm result: 2.41
One of our analysts is saying that all we should do is multiply the PPM result by the 100 dilution factor and report this result as ppm:
- [machine ppm (2.41) * dilution factor (100)] = 241ppm
The other analyst is saying we should account for weight of test sample and apply a correction to bring it per constant weight (0.1g) (?) and report as mg/kg:
- [Correcting to 0.1g (0.1) / sample weight(g) (0.1016) ] = 0.9843
- [0.9843 * machine ppm (2.41)] = 2.3721ppm
- [2.371ppm * dilution factor (100)] = 237 mg/kg
What is the difference between ppm and mg/kg? Can anybody offer any input into clarifying the calculation or how they would go about this?
Thank you.
There are two analysts in my work that are disagreeing on how to process HPLC data. I'm not sure with which way to go.
We are analysing an impurity in a solution of various components - acids, methanol etc. Our goal is to determine if the solution contains <1,000ppm of impurity and if so, it's good to be used.
We pipette 0.1ml into a 10ml volumetric flask, record the actual weight of the sample and make up to the mark with ultrapure water and then obtain a ppm result from the HPLC.
Parameters:
Dilution factor: 100
Example sample weight (0.1ml sample): 0.1016g
Example Machine ppm result: 2.41
One of our analysts is saying that all we should do is multiply the PPM result by the 100 dilution factor and report this result as ppm:
- [machine ppm (2.41) * dilution factor (100)] = 241ppm
The other analyst is saying we should account for weight of test sample and apply a correction to bring it per constant weight (0.1g) (?) and report as mg/kg:
- [Correcting to 0.1g (0.1) / sample weight(g) (0.1016) ] = 0.9843
- [0.9843 * machine ppm (2.41)] = 2.3721ppm
- [2.371ppm * dilution factor (100)] = 237 mg/kg
What is the difference between ppm and mg/kg? Can anybody offer any input into clarifying the calculation or how they would go about this?
Thank you.