okkk thanks.. but.... why 50/250? or why a fraction and not an equivalence?
Don't know exactly what you mean.
50 µg of [Cl]- give a certain turbidity.
if the same turbidity is observed in your test solution, then you would have 50 µg [Cl]- in 250 mg of your sample, which is an amount of 200 ppm.
The test states that the turbidity is less than that of 50 µg of [Cl]-, so your amount is < 200 ppm
The test should also work if you take 1 ml of a 50 ppm standard and add 14 ml of water, or 5 ml of a 10 ppm plus 10 ml of water, and so on.
Goal is to have 50 µg of chlorine-ions in 15 ml of solution before adding the nitric acid and silver nitrate.