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- Posts: 110
- Joined: Fri Aug 07, 2009 1:40 pm
I think dilution of 0.40 mg in 10 mL will give you 0.04 mg/mL. Then to make 1/5, 1/10, 1/25, 1/100 dilution this will give you 0.008, 0.0044, 0.0018, and 0.00044 mg/mL
So I feel they forgot to add zero
Am I right?
Kindly see the statements below:
Standard Preparation and Calibration Curve. Commercially
available standards of cyanidin-3-rutinoside chloride
(keracyanin chloride, 0.40 mg) and cyanidin-3-glucoside chloride
(kuromanin chloride, 0.35 mg) were separately dissolved
in 2% HCl/MeOH solution (v/v) (10 mL), and used as standard
stock solutions for generating calibration curves. The stock
solutions were diluted 1/5, 1/10, 1/25, and 1/100 times in 2%
HCl/MeOH (v/v) to afford 0.08, 0.044, 0.018, and 0.0044 mg/
mL solutions of cyanidin-3-rutinoside chloride and 0.07, 0.035,
0.014, and 0.0035 mg/mL solutions of cyanidin-3-glucoside
chloride, respectively. These four standard solutions and the
stock solution were injected to generate a five point calibration
curve for the two standard compounds separately, using
Millennium chromatography manager. Standard curve was
linear with R2 ) 0.9998. Peak areas of the target compounds
were within the linear range of the curve. Relative standard
deviations for two injections per standard (for set of five
standard solutions) were less than 2.0%.