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- Posts: 1
- Joined: Wed Aug 05, 2015 4:13 am
I have apple tubers. I would like to test their peel for existence of compound A. This compound A remains 98% on its peel. So taking the peel is enough
Method:
Tubers weight= 0.5 kg ( this is total from many tuber not only one )
Weight of total peel = 50 g
weight of peel sample that I took = 5 g
so I extract this 5 g by 40 ml solvent ( soaking 24 hours then filter and measure by HPLC ).
Now, how much ( mg/kg) of compound A in the whole tuber?.
My answer:
concentration in extract ( the one I made by 5 g plus 40 ml after filtration) = 1 microgram/ml
multiply this by 40 to get 40 microgram in 5 g peel
so in 50 g this will be 400 microgram/ 50 g
in 500 g ( 0.5kg) this will be 4000 microgram/500g
divide 4000/500
so in the whole tuber will be 8 mg/kg
my colleagues said use this formula but it did not give like my answer. It gave 0.8 while mine is 8
Also I am worry why we have to include tuber weight while we depend only on the tuber peel ( 5 g ) and how much compound A is in there
this formula is
concentration in tuber mg/kg = ( conc. in extract* vol 40 ml* wight of total peel )/ ( weight of peel sample*weight of tuber)
Is my answer correct, if you provide me with more practice thats will be very excellent
thanks