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- Posts: 14
- Joined: Sun Jul 24, 2011 10:36 pm
There has been at leat one huge discussion of the matter on this very board some years ago if memory servs me.
Best Regards
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Even if you are, this is the best explanationHmmm, I thought it was H/(h/2) ... hence 2*H/h ?
I could be wrong though!
To my knowledge all CDS do that. If there is a single CDS that does not – we need to clarify what that particular one does. If you look at the Kwet80 post above you’ll se how a typical peak is plotted and then you can imagine how the integration application will proceed. Have you seen other options?The fact that an integrator might (but not all do) choose the lowest point in the noise for its baseline and the highest point for the top of its peak is a different issue to where the factor of 2 comes in.
The integrator (The CDS) will not calculate anything like this. The software will calculate peak height and the nose. You’ll have to edit a formula/equation and then you can choose to include the factor of 2.If the integrator does this, it is overestimating H, the height of the peak, but it doesn't affect its estimate of h, the lowest-to-highest height of the noise. What it's calculating is (H+h)/h, or 2*(H+h)/h according to definition.
Yeah - not least because they are hugely overestimated. So, you’d like to make things twice as worse by multiplying the signal (peak height) by 2.I'm in agreement with Peter, that S/N is a poor way to estimate LOD or LOQ
Here I am quite confuse. What is H and h? I am new to this and am also stucked in this situtation.
Ya M serious. Coz m new to this. I've performed AMV for one of our product. As I am doing right the first time, m confuse which value should be considered for H and h.You are not serious - are you?
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